Assuming standard display conditions, our 80mm lens used on a FF camera at f/4.5 focused at 50 feet would give us a total DoF of 35.5 feet with 12.1 feet in front of the point of focus and 23.4 ft behind the point of focus. ¹ Though the total DoF would be almost the same, the distribution of that DoF in front of and behind the point of focus could be different. ![]() The more we must enlarge an image to view it at a specific display size, the larger we make all of the blur in the image, and the easier it is for our eyes to be able to tell that the same amount of blur, as measured on the sensor before we enlarged it, is blurry. ![]() Remember, in a way DoF is really an illusion that is determined by exactly how large blur can be before our eyes can see that blur as "blurry" versus how small blur must be to still look sharp and in focus to our eyes. But we'd still get exposure equivalent to f/2.8 with an 80mm lens used on the FF camera.We'd also get depth of field that looks about the same¹ as if we had used f/4.5 with the 80mm lens on the FF camera.We would get a field of view that would be equivalent to using an 80mm lens on a FF camera.1.6X wider and 1.6X taller) sensor.įor example, if we use a 50mm lens at f/2.8 on our Canon APS-C camera with a crop factor of 1.6X, then: When we use a 1.6X cropped sensor, the change in depth of field is very close to the change in depth of field that would be the case if we used a 1.6X longer lens with a 1.6X higher f-number on a FF ( i.e. The difference is that when we take the image collected using a smaller sensor and enlarge it to be viewed at the same display size as an image taken with the same focal length lens using a larger sensor, we must enlarge the image from the smaller sensor more. So an f/2.8 entrance pupil is still 17.9mm wide for that 50mm lens. Remember, our focal length didn't really change, only the angle of view actually changed due to using a smaller sensor. With regard to "aperture", what does change is depth of field (DoF) or depth of focus (DoF). "close enough for government - or photographic - work") what we get when we multiply 2.8 by our 1.6X conversion factor (and, of course, 1.6X is the same ratio between 50mm and 80mm). If our lens is 80mm and has a diameter of 17.9mm, though, that gives us f/4.5. ![]() If our lens is 80mm, f/2.8 is an aperture 28.6mm in diameter. If our lens is 50mm, f/2.8 has an aperture of 17.9mm. But strictly speaking, the aperture is a diameter of an opening, not the ratio of that diameter to the focal length. The lens focal length divided by the diameter of the aperture, more properly called the entrance pupil, is the f-number that we often call the "aperture". When we say we used an aperture of f/2.8, for instance, what we're really saying is we used an aperture that was 1/2.8 in diameter compared to the lens' focal length. It's used to determine how much light per unit area falls on a sensor or film over a specific time period (the exposure time or "shutter speed"). This is because the f-number is a dimensionless ratio. With regard to "aperture", what doesn't change is exposure. We often associate a specific angle of view with a particular focal length and film size, and when we say using a crop sensor "changes" the focal length what we are really saying is that using a crop sensor changes the angle of view as compared to using the same focal length with a 36x24 mm piece of film or a "full frame" sensor that is essentially the same size as the 135 format (i.e. (We are assuming neither the focal length, f-number, the camera position, nor the focus distance to our subject changes - only the size of our camera's sensor.) ![]() What does change is the angle of view and the depth of field, but not the exposure. Neither the focal length of the lens nor the aperture of the lens change if we change the size of the sensor.
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